WebFeb 15, 2016 · How do you solve for a in S A = 2ab + 2ac + 2bc? Algebra Linear Equations Formulas for Problem Solving 1 Answer Noah G Feb 15, 2016 Put the terms that contain a's alone on one side of the equation and factor out the a. Explanation: SA −2bc = 2ab + 2ac SA −2bc = 2a(b + c) SA −2bc b + c = 2a SA −2bc 2b + 2c = a Practice Exercises: Solve for x WebApr 13, 2024 · Video Giải bài tập Toán 8 trang 12)
Simplify: a2+b2-c2-2ab/a2-b2-c2+2ab-b2-c2-2bc/a2-b2-c2+2bc …
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WebPlease take me through the process step by step. a ∗ b = a + b + 2 a b Where ∗ is a binary operation and a and b are real numbers. I have got this far: ( a ∗ b) ∗ c = a ∗ ( b ∗ c) So ( a + b + 2 a b) ∗ c And a ∗ ( b + c + 2 b c) I am not sure what the next step would be. Many thanks, Conor group-theory binary-operations associativity Share Web已知a、b、c是 ABC的三边,且满足关系式a²+c²=2ab+2ac-2b²,试判断 ABC是否为特殊三角形 相关知识点: 试题来源:巢湖市2016-2024学年八年级上期末教学质量数学试题附答案 WebMar 26, 2024 · Step-by-step explanation: The given expression can be factorised as follows: a² + b² + 2ab + 2bc + 2ac Using the identity (a + b)2 = a2 + b2 + 2ab Applying formula,we get ⇒ (a + b)² + 2 (bc + ca) Looking for common sub-expressions : (a + b) ⇒ (a + b)² + 2c (b + a) ⇒ (a + b) (a + b + 2c) Can't be factorized any more. the year 1945